(x/100)+(y/66)=(3x+5y/z)
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In this question there is an mistake. You wrote (x/100)+(y/66)=(3x+5y)/z but it must be
(x/110)+(y/66)=(3x+5y)/z I tried both questions so it must be the second
(66x+110y)/7260=(3x+5y)/z
(66x+110y) / (3x+5y) = 7260 / z
22 = 7260 / z
22z = 7260
z = 330
Which it is C
(x/110)+(y/66)=(3x+5y)/z I tried both questions so it must be the second
(66x+110y)/7260=(3x+5y)/z
(66x+110y) / (3x+5y) = 7260 / z
22 = 7260 / z
22z = 7260
z = 330
Which it is C
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