Question

x= 10t²+20t+5 y=5t²+4t+5 find v at t=2
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Answer 1

Answer:

This question does not require calculus, just some basic physics. An average velocity is defined by the distance moved divided by the time taken for that movement. So, we have a time duration T = 3 - 2 = 1 second. There is the position at T = 2, I will call it Ptwo, in which X = 10 * 2^2 = 40 meters. The final position at T = 3, called Pthree is X = 10 * 3^2 = 90 meters. The distance traveled in the one second is (Pthree - Ptwo) = (90 - 40) = 50 meters, moving toward larger X, so the velocity is positive. The average velocity is +50 meters/second.