Question

(x^12/3xy^4)^-2how to solve this ​

Answer 1

Answer:

$( \frac{ {x}^{12} }{3x {y}^{4} }) ^{ - 2}$

$first \: remove \: minus \: from \: power$

$( \frac{3x {y}^{4} } { {x}^{12} }) ^{2}$

$\frac{9 {x}^{2} {y}^{8} }{ {x}^{24} }$

$9 {x}^{2} {y}^{8} \div {x}^{24}$

$9 {x}^{2 - 24} {y}^{8}$

$9 {x}^{ - 22} {y}^{8}$

$\frac{9 {y}^{8}}{ {x}^{22} }$

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