Math, asked by ikrakhan79, 11 months ago

x^2+1/2x^2=23 than find the value of x-1/x​

Answers

Answered by baratzind97
0

 \frac{ {x}^{2} + 1 }{ {2x}^{2} }  = 23 \\  \\   {x}^{2}  + 1 =  {46x}^{2}  \\  \\  {46x}^{2}  -  {x}^{2}  = 1 \\  \\  {45x}^{2}  = 1 \\ x =  \sqrt{ \frac{1}{45} }  \\  \\ x =  \frac{1}{3 \sqrt{5} }  \\ x =  \frac{3 \sqrt{5} }{45}   \\ x =  \frac{ \sqrt{5} }{15} \\  \\  \frac{1}{x}  =  \frac{1}{ \frac{ \sqrt{5} }{15} }  \\  \\  \frac{1}{x}  = \frac{15}{ \sqrt{5} }  \\  \frac{1}{x }  =  \frac{15 \sqrt{5} }{5} \\  \frac{1}{x}   =  \frac{3 \sqrt{5} }{5} \\ x -  \frac{1}{x}  =  \frac{ \sqrt{5}  - 9 \sqrt{5} }{15}   =  \frac{ - 8 \sqrt{5} }{15}

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