||x-2|-1|>= 3
find the value of x
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Given equation: ||x - 2| - 1| ≥ 3
Find that exactly at which value is the result equal to 3, since the numbers are being subtracted, see the pattern of results from keeping value of x as 2 to (-2). At x = -2, the result is 3. And before that, all the results are less than 3. Thus, for all values less than -2, the result will be greater than 3.
Keep x = -2
Result = 3
Since 3 = 3, x = -2
So, x € [-2, -infinity]
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