Question

X^2+1/x^_3
x square + 1 by x square - 3 solve this equation

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

${x}^{2} + \frac{1}{x} - 3 \\ =( {x}^{3} + 1 - 3x) \div x \\ = \frac{x ^{3} - 3x + 1 }{x} \\ = \frac{ {x}^{3} - x - x - x + 1}{x} \\ = \frac{ {x}^{2}(x - 1) -1 \times (x - 1) - x }{x} \\ = \frac{(x^{2 } - 1)(x - 1) - x}{x} \\ = \frac{(x {?}^{2} - 1)(x - 1) }{x} - 1$