Question

(x^2-1)(x^4+x^2+1)evaluate

Answer 1

( x^{2} -1)( (x^{4} +x^{2} +1) )

If we evaluate, we will multiply both the brackets or parenthesis.

Firstly, we will multiply the x^2 to second bracket all the terms and same steps with -1

$x^{2} (x^{4}) + x^{2}(x^{2} ) + x^{2} (1) - 1(x^{4}) -1(x^{2} ) -1(1)$

If base are same then we add the power (for example: $x^{3}( x^{5}) = x^{(3+5)} = x^{8}$)

$x^{6} + x^{4} + x^{2} - x^{4} - x^{2} - 1$

cancel out the same terms with opposite sign

$x^{6} -1$

Answer 2

(x^6+x^4+x^2-x^4-x^2+1)
=x^6+1