x^2+1/x=5.....Find value of x^2+1/x^2
Answers
Answered by
2
Hi Friend !!!
Here is ur answer,,,
x+1/x = 5
Squaring on both sides ,
(x+1/x)² = 5²
x²+1/x² + 2(x)(1/x) = 25
x²+1/x² + 2 = 25
x²+1/x² = 25-2
x²+1/x² = 23
Hope it helps u : )
Here is ur answer,,,
x+1/x = 5
Squaring on both sides ,
(x+1/x)² = 5²
x²+1/x² + 2(x)(1/x) = 25
x²+1/x² + 2 = 25
x²+1/x² = 25-2
x²+1/x² = 23
Hope it helps u : )
Answered by
0
Answer:
23
Step-by-step explanation:
( x + 1 /x ) = 5
( x + 1 / x )^2 = 25
= x^2 + 1 / x^2 + 2 * x * 1/x =25
= x ^2 + 1/x^2 + 2 = 25
= X^2 + 1 / x^2 = 25 - 2 = 23
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