Question

x^2-10x+21 divided by x^2-5x+6 then find the remainder and quotient

Answer 1

Here is your answer....

Quotient =1

Remainder = -5x +15

Answer 2

$\frac{x^{2} - 10x + 21}{ {x}^{2} - 5x + 6 } = - 5x + 15$

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