Math, asked by srivasbasudev, 11 months ago

x^2-10x+21 find the factors of this polynomials

Answers

Answered by Anonymous
2

Answer:

x²-10x+21 = 0

x²-3x-7x+21 = 0

x(x-3)-7(x-3) = 0

x = 3, 7

hope it helps

Answered by sujeetsahani8745
5

x²-10x+21

x²-3x-7x+21

x(x-3)-7(x-3)

(x-7)(x-3)

I Hope it's help you

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