x^2-10x+21 find the factors of this polynomials
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2
Answer:
x²-10x+21 = 0
x²-3x-7x+21 = 0
x(x-3)-7(x-3) = 0
x = 3, 7
hope it helps
Answered by
5
x²-10x+21
x²-3x-7x+21
x(x-3)-7(x-3)
(x-7)(x-3)
I Hope it's help you
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