Question

x^2 + 10x +7√3 find roots by quadratic formula method
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Answer 1

Step-by-step explanation:

x^2 + 10x +7√3

b^2-4ac = 100 - 28√3

= 51.6

-b + √ b^2-4ac /2a or -b - √ b^2-4ac /2a

-10 + √51.6 /2 or -10 - √51.6 /2

hope it helps you buddy

Answer 2

Answer:

I

Step-by-step explanation:

It is Given That,

${x}^{2} + 10x + 7 \sqrt{3}$

Now we Know,

$a = 1 \: \: \: \: b = 10 \: \: \: \: \: c = 7 \sqrt{3}$

Now we Know,

Quadratic Formula Is Given By;

$= > \frac{ - b \frac{ + }{ } \sqrt{ {b}^{2} - 4ac } }{2a}$

Putting The Value of a,b,c

We Get

$= > \frac{ - 10 \frac{ + }{} \sqrt{ {10}^{2} - 4 \times 1 \times 7 \sqrt{3} } }{2 \times 1}$

$= > \frac{ - 10 \frac{ + }{} \sqrt{100 - 28 \sqrt{3} } }{2}$

So Roots Are,

$x = \frac{ - 10 + \sqrt{100 - 28 \sqrt{3} } }{2} or \: \frac{ - 10 - \sqrt{100 - 28 \sqrt{3} } }{2}$

Hence Solved..

Hope it Helped You!!!!