Question

x^2+12/35x + 1/35 plz help me it is urgent​

Answer 1

Answer :

• x² + 12/35x + 1/35 = - 1/5 or - 1/7

Given :

• x² + 12/35 x + 1/35

To find :

• Factors

Solution :

➟ x² + 12/35x + 1/35

➟ 35x² + 12x + 1 / 35 = 0

➟ 35x² + 12x + 1 = 0

➟ 35x² + 7x + 5x + 1 = 0

➟ 7x(5x + 1) + 1x(5x + 1) = 0

➟ (5x + 1) (7x + 1) = 0

➟ 5x + 1 = 0 or 7x + 1 = 0

➟ x = - 1/5 or x = - 1/7

Hence, x² + 12/35x + 1/35 = - 1/5 or - 1/7

Answer 2

Question :

x^2+12/35x + 1/35

Solution :

${x}^{2} + \frac{12x}{35} + \frac{1}{35}$

So as 12x/ 35 and 1/35 has a common denominator hence no for getting L.C.M

$\sf \longmapsto {x}^{2} + \frac{12x + 1}{35}$

$\sf \longmapsto \frac{35 {x}^{2} + 12x + 1 }{35}$

$\sf \longmapsto35 {x}^{2} + 12 + 1 = 35$

After this we need to split 12 by middle term factorisation

$\sf \longmapsto 35{x}^{2} + (7 + 5)x + 1 = 35$

$\sf \longmapsto 35{x}^{2} + 7x + 5x + 1 = 35$

Now we need to factorise the terms on the L.H.S

$\sf \longmapsto7x(5x + 1) + 1(5x + 1) = 35$

Here in the second one nothing common means 1 will be written because 1 can be multiplied by all the no.s

$\sf \longmapsto(5x + 1)(7x + 1) = 35$

After this 5x + 1 = 35 and 7x + 1 = 35

5x = 34

x = 6.8

7x = 34

x = 4.857

So the result can be either 6.8 or 4.857