Question

x^2+12x-20/3x-5 =x^2+8x+12/2x+3

Answer 1

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Answer 2

$x=\dfrac{-12}{13}$

Step-by-step explanation:

We have,

$x^{2} +12x-\dfrac{20}{3}x-5=x^{2}  +8x+\dfrac{12}{2}x+3$

To find, the value of x = ?

∴$x^{2} +12x-\dfrac{20}{3}x-5=x^{2}+8x+\dfrac{12}{2}x+3$

⇒ $12x-\dfrac{20}{3}x-5=8x+\dfrac{12}{2}x+3$

⇒ $12x-\dfrac{20}{3}x-5=8x+6x+3$

⇒ $12x-\dfrac{20}{3}x=14x+3+5$

⇒ $-2x-\dfrac{20}{3}x=8$

⇒ $\dfrac{-6x-20x}{3}=8$

⇒ $-26x=24$

⇒$x=\dfrac{-24}{26} =\dfrac{-12}{13}$

Hence, $x=\dfrac{-12}{13}$.