Question

x^2 -16x + k =0 then find the value of k

Answer 1

Hi,

Here is your answer

x² - 16x + k = 0
Therefore the roots are real and equal.
b² - 4ac = 0
(-16)² - 4*1*k = 0
256 - 4k = 0
4k = 256
k = 256/4 = 64
The value of k is 64.

Hope this helps you.