Question

x^2-18x+81=4
write the equation in this form (x+p)^2=q

Answer 1

Step-by-step explanation:

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x^2-18*x+81-(4)=0

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring x2-18x+77

The first term is, x2 its coefficient is 1 .

The middle term is, -18x its coefficient is -18 .

The last term, "the constant", is +77

Step-1 : Multiply the coefficient of the first term by the constant 1 • 77 = 77

Step-2 : Find two factors of 77 whose sum equals the coefficient of the middle term, which is -18 .

-77 + -1 = -78

-11 + -7 = -18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -11 and -7

x2 - 11x - 7x - 77

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-11)

Add up the last 2 terms, pulling out common factors :

7 • (x-11)

Step-5 : Add up the four terms of step 4 :

(x-7) • (x-11)

Which is the desired factorization