(x-2)^2+2(x-2)-8 factorize
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Question-:
(x-2)^2+2(x-2)-8
Answer-:
(x-2)^2+2(x-2)-8
=(x-2) [ (x-2) +2 ]-8
=(x-2) [ (x-2+2 ]-8
=(x-2) [x]-8
=x^2 - 2x -8
= x^2 -4x + 2x - 8
=x [x-4] + 2 [x-4]
= [x-4] [x+2]
Hope it's clear. Please mark it as the brainliest...
(x-2)^2+2(x-2)-8
Answer-:
(x-2)^2+2(x-2)-8
=(x-2) [ (x-2) +2 ]-8
=(x-2) [ (x-2+2 ]-8
=(x-2) [x]-8
=x^2 - 2x -8
= x^2 -4x + 2x - 8
=x [x-4] + 2 [x-4]
= [x-4] [x+2]
Hope it's clear. Please mark it as the brainliest...
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