Question

(x-2)^2+2(x-2)-8 factorize

Answer 1

Question-:

(x-2)^2+2(x-2)-8

Answer-:

(x-2)^2+2(x-2)-8

=(x-2) [ (x-2) +2 ]-8

=(x-2) [ (x-2+2 ]-8

=(x-2) [x]-8

=x^2 - 2x -8

= x^2 -4x + 2x - 8

=x [x-4] + 2 [x-4]

= [x-4] [x+2]

Hope it's clear. Please mark it as the brainliest...