Question

x^2+2√2x-6=0 solve by quadratic formula​

Answer 1

Step-by-step explanation:

x2+22x−6=0

x2+32x−2x−6=0

x(x+32)−2(x32)=0

(x+32)(x−2)=0

Either (x+32)=0, then x=−32

or x−2=0, then x=2

x=2 or −32

Answer 2

★ Required Solution:

Given quadratic equation:

x²+2-√2x-6=0

Splitting the middle term, we get

x²+3√2x-√2x-6-0

=>x²+3√2x-√2x-√2*3√2=0

=> x(x+3√2)-√2(x+3√2)=0

=> (x+3√2)(x-√2)=0

=> x+3-√2-0 Or x-√2=0

=> x = -3√2 Or x = √2

Therefore,

✥ Roots of given quadratic equation:

x = -3-√2 Or x = √2