Question

-x^2 + 2×3^1/2 + 9 = 0 ,find x​

Answer 1

$-x^{2} + 2\sqrt{3}x + 9 = 0$

/* Splitting the middle term,we get

$\implies - x^{2} + 3\sqrt{3}x - \sqrt{3}x + 9 = 0$

$\implies -x( x - 3\sqrt{3}) - \sqrt{3} ( x - 3\sqrt{3}) = 0$

$\implies (x-3\sqrt{3})(-x-\sqrt{3}) = 0$

$\implies x-3\sqrt{3}=0\: Or \: -x-\sqrt{3}= 0$

$\implies x = 3\sqrt{3}\: Or \: x = - \sqrt{3}$

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