x^2 - 2/5xy + y^2/25 - 1 factorize the following by completing the squares
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x^2 - 2/5xy + y^2/25 - 1
= (x)^2 - 2 (x) (1/5)y + (y/5)^2 - 1
= (x - y/5)^2 - (1)^2
= (x - y/5 + 1) (x - y/5 -1)
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