Question

(x+2)^2 -
$(x + 2) {}^{2} - (x + 4) {}^{2}$
​

Answer 1

$\huge{ Answer = -3\:}$

${(x + 2)}^{2} - ( {x + 4)}^{2} \\ ({x }^{2} + 4x + 4) - ({x}^{2} + 8x + 16) \\ {x}^{2} + 4x + 4 - {x}^{2} - 8x - 16 \\ - 4x - 12 \\ - 4x = 12 \\ x = - \frac{12}{4} \\ x = - 3$

✌️Hope this will helps you ✌️

Answer 2

$\LARGE{\sf{Correct \: Question }}$

Find Value of x.

(x + 2)² - (x + 4)² = 0

==========================

$\Huge{\star}{\underline{\boxed{\red{\sf{Answer :}}}}}{\star}$

$\large{\sf{[x^2 \: + \: (2)^2 \: + \: 2(x)(2)] \: - \: [x^2 \: + \: (4)^2 \: + \: 2(x)(4)]}}$

$\large{\sf{x^2 \: + \: (2)^2 \: + \: 2(x)(2) \: - \: x^2 \: - \: (4)^2 \: - \: 2(x)(4)}}$

$\large{\sf{\cancel{x^2} \: + \: 4 \: + \: 4x \: - \: \cancel{x^2}\: - \: 16 \: - \: 8x}}$

$\large{\sf{4 \: + \: 4x \: - \: 16 \: - \: 8x}}$

$\huge \implies {\boxed{\sf{-4x \: - \: 12 \: = \: 0}}}$

$\large{\sf{-4x \: = \: 12}}$

$\large{\sf{x \: = \: \frac{12}{-4}}}$

$\Huge \implies {\boxed{\boxed{\sf{x \: = \: -3}}}}$