(x-2)^2 + (y-3)^2 + (z-5)^2 = 0 Then show that x+y+z = 0.
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(x-2)² + (y-3)² + (z+5)² = 0
so from property we know that when a² + b² + c² = 0
then a=b=c=0
so here
also x-2 = 0 ⇒ x = 2
y - 3 = 0 ⇒ y = 3
z+ 5 = 0 ⇒ z = -5
so x + y + z = 2 + 3 - 5 = 0 PROVED
so from property we know that when a² + b² + c² = 0
then a=b=c=0
so here
also x-2 = 0 ⇒ x = 2
y - 3 = 0 ⇒ y = 3
z+ 5 = 0 ⇒ z = -5
so x + y + z = 2 + 3 - 5 = 0 PROVED
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(2x-y)^2 + (3y-2z)^2 = 0, Find x:y:z.
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