Math, asked by harsh102006, 8 months ago

X^2-(2b-1)x+(b^2-b-20)=0 find roots by completing the square method​

Answers

Answered by sgadiya44
0

Answer:

x² + x + b² - b - 2bx - 20 = 0

Step-by-step explanation:

x² - (2b - 1)x + (b² - b - 20) = 0

x² - 2bx + x + b² - b - 20 = 0

x² + x + b² - b - 2bx - 20 = 0

HOPE THIS WILL HELP YOU!

Similar questions