Question

X^2-(2p-1)x+(p^2-p-20)=0. x=??

Answer 1

Answer:

given roots are equal so b^2-4ac=0

(2p-1)^2-4*1*p^2=0

4p^2-4p+1-4p^2=0

-4p+1=0

p=1/4

Step-by-step explanation:

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Answer 2

Answer:

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