Question

-x^2+2x-10=0 Solve this using the quadratic formula

Answer 1

Answer:

-2-3i and -2+ 3i

Step-by-step explanation:

roots of quadratic equation formula is

$-b +-(\sqrt{ ({b}^{2} - 4ac)} \div 2a)$

here a= -1, b= 2,c= -10

put these values in formula

$-2+-(\sqrt{( {2}^{2} - 4( - 1) ( - 10))} \div ( - 2))$

this becomes

$-2( \sqrt{( - 36) } \div ( - 2))$

negative value in root becomes i after solving

$-2+-(6i \div ( - 2))$

so -2-3i and -2+3i