Question

X^2-2x^2-x+2 plzz answer my question and be faster

Answer 1

$=-\left(x-1\right)\left(x+2\right)$

Step-by-step explanation:

Given x^2-2x^2-x+2

=$-x^2-x+2$

$\mathrm{Factor}\:-x^2-x+2:\quad -\left(x-1\right)\left(x+2\right)\\steps\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(x^2+x-2\right)\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(x^2-x\right)+\left(2x-2\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-x\mathrm{:\quad }x\left(x-1\right)\\\mathrm{Factor\:out\:}2\mathrm{\:from\:}2x-2\mathrm{:\quad }2\left(x-1\right)\\=x\left(x-1\right)+2\left(x-1\right)\\=\left(x-1\right)\left(x+2\right)$

$=-\left(x-1\right)\left(x+2\right)$

Answer 2

Answer:

The factors are (x-1), (x+1) and (x-2)

Step-by-step explanation:

I think your question may be

$Factorize:\:x^3-2x^2-x+2$

$Formula\:used:\\\\a^2-b^2=(a+b)(a-b)$

$Now,\\\\x^3-2x^2-x+2\\\\=x^2(x-2)-1(x-2)\\\\=(x^2-1)(x-2)\\\\=(x^2-1^2)(x-2)\\\\=(x-1)(x+1)(x-2)$