x^2-2x=√(2x^2-4x+3)
solve for x
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Answer:
To answer your specific question: yes, squaring introduces additional "sol.utions" which you do not want. So you have to check at the end.
Squaring gives (x2−2x)2−2(x2−2x)−3=0 or
(x2−2x−3)(x2−2x+1)=0
so x=1,−1 or 3.
But checking we find that x=1 is not a solution to the original equation.
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