Question

X^2+2x-38=0 solve by factorisation

Answer 1

Answer:

⇢ $\sf{-1 \pm \sqrt{39}}$

Step-by-step explanation:

⇢ $\sf{x^{2} + 2x - 38 = 0}$

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⇢ $\sf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}$

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⇢ $\sf{x = \dfrac{-(2) \pm \sqrt{(2)^{2}} - 4 (1) (-38)}{2 (1)}}$

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⇢ $\sf{ = \dfrac{-2 \pm \sqrt{156}}{2}}$

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⇢ $\sf{-1 \pm \sqrt{39}}$

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Therefore, this is the required answer.

Note:-

• I used 'quadratic equation' to solve this equation.