Question

x^2 +2x-7 = (x+a)^2+b
solve for a and b

Answer 1

Step-by-step explanation:

x^2 +2x-7 = (x+a)^2+b

x^2 +2x-7 = (x^2 + a^2 + 2*x*a)+b

For a = ( x^2 +2x - b - 7 - x) ^-1/2

b =−a(2x+a)+2x−7

Answer 2

Answer= a=+1 and b= -8

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