Question

[x^2-2xy-y^2]dx-(x+y^2) dy = 0​

Answer 1

Answer:

x^2+2xy-y^2).dx +(y^2+2xy-x^2).dy=0 or. dy/dx =(y^2-2xy-x^2)/(y^2+2xy-x^2) Let y=v.x dy/dx=v .1+x.dv/dx ...