Question

x/2+2y/3=-1 ; x-y/3=3

Answer 1

mark it as brainalist answer

Answer 2

$\underline{\bold{Answer:-}}$


$\\ \frac{x}{2} + \frac{2y}{3} = - 1 \\ \\taking \: \: lcm \\ \\ = > \frac{3x + 4y}{6} = - 1 \\ \\ = > 3x +4 y = - 6 - - - (1)$
$\\ x - \frac{y}{3} = 3 \\ \\ taking \: \: lcm \\ \\ = > \frac{3x - y}{3} = 3 \\ \\ = > 3x - y = 9 - - - (2)$

$3x +4 y = - 6 - - - (1) \\ \\ 3x - y = 9 - - - (2)$

By Elimination method


$3x +4 y = - 6 \\ 3x - y \: = \: \: \: \: \: 9 \\ ( - ).( + ).( - ) \\ - - - - - - - - \\ \\ = > 5y = - 15 \\ \\ = > y = \frac{ - 15}{5} \\ \\ = > y = - 3$

From eq'n ( 1 )

$3x + 4y = - 6 \\ \\ = > 3 x + 4( - 3) = - 6 \\ \\ = > 3x - 12 = - 6 \\ \\ = > 3x = - 6 + 12 \\ \\ = > 3x = 6 \\ \\ = > x = \frac{6}{3} \\ \\ = > x = 2$



Hence the value of x = 2 and y = - 3.

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Verification


Equation: - ( 1 )

3x + 4y = - 6

Putting the value of x and y

$= > 3(2) + 4( - 3) = - 6 \\ \\ = > 6 - 12 = - 6 \\ \\ = > - 6 = - 6$

LHS = RHS


Equation: - ( 2 )

3x - y = 9

Putting the value of x and y


$= > 3(2) - ( - 3) = 9 \\ \\ = > 6 + 3 = 9 \\ \\ = > 9 = 9$
LHS = RHS



Hence, it is verified ✔✔




$\textbf{Hope it helps!}$