X^2 + 3^3 = 31 what is the value of x here???
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Answered by
1
Answer:
x^2+3^3=31
We move all terms to the left:
x^2+3^3-(31)=0
determiningTheFunctionDomain
x^2-31+3^3=0
We add all the numbers together, and all the variables
x^2-4=0
a = 1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·1·(-4)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ−−√=16−−√=4
x1=−b−Δ√2a=−(0)−42∗1=−42=−2
x2=−b+Δ√2a=−(0)+42∗1=42=2
Step-by-step explanation:
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