x-2/3+x-3/4=x-1/2 take out x
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Step-by-step explanation:
Given:-
(x-2)/3+(x-3)/4=(x-1)/2
To find:-
Find the value of x ?
Solution:-
Given equation is (x-2)/3+(x-3)/4=(x-1)/2
LCM of 3 and 4 = 13
=> [4(x-2)+3(x-3)]/12 = (x-1)/2
=> (4x-8+3x-9)/12 = (x-1)/2
=> (7x-17)/12 = (x-1)/2
On applying cross multiplication then
=> 2(7x-17) = 12(x-1)
=> 14x -34= 12x-12
=> 14x -12x = -12+34
=> 2x = 22
=> x = 22/2
=> x = 11
Answer:-
The value of x for the given problem is 11
Check:-
If x = 11 then
LHS = (x-2)/3+(x-3)/4
=> (11-2)/3 + (11-3)/4
=> (9/3) + (8/4)
=> 3+2
=> 5
RHS =(x-1)/2
=> (11-1)/2
=> 10/2
=>5
LHS = RHS is true for x = 11
Verified the given relations.
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