Question

(x+2)³=x3-4 is quadratic equation? explain

Answer 1

Answer:

This equation $6x^{2} +12x +12=0$ is quadratic equation.

Step-by-step explanation:

Given: The equation is $(x+2)^{3}=x^{3} -4$

To find $(x+2)^{3}=x^{3} -4$ is quadratic equation.

We have the equation $(x+2)^{3}=x^{3} -4$

Using cube formula $(a+b)^{3}= a^{3}+b^{3}+3ab(a+b)$

$(x)^{3}+2^{3}+3(x)(2)(x+2) =x^{3} -4$

Solving.

$x^{3}+8+6x^{2} +12x =x^{3} -4$

Then

$x^{3}+8+6x^{2} +12x -x^{3} +4=0$

$6x^{2} +12x +12=0$

Thus, the obtained equation $6x^{2} +12x +12=0$ is a quadratic equation of the form $ax^{2} +bx +c=0$ where the coefficient of $x^{2}$ is $a=6\neq 0$

Hence, $6x^{2} +12x +12=0$ is a quadratic equation.

Answer 2

Given, (x+2)³=x3-4

To Find the above equation is it a quadratic equation?

Solution;