x^2 - 3x-10 =0 solve by completing square
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x^2 + 3x -10...(here already the a=1)
(3/2)^2= 9/4 ......(squaring the middle term)
x^2+3x +9/4=10+9/4.....(added to b.s)
(x + 3/2)^2 = 49/4
taking √ b.s we get
x+3/2 = +7/2 and -7/2
therefore, x=7/2-3/2 and x=-7/2-3/2
i.e x=2 or x= -5
hope it helps
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