Question

x^2-3x+2=0, x=2 or x=-1 is the root of the equation
plsss answer fasssstt​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Given data,

${x}^{2} - 3x + 2 = 0 \\ {x}^{2} - 2x - x + 2 = 0 \\ x(x - 2) - (x - 2) = 0 \\ (x - 1)(x - 2) = 0 \\ therefore \\ x - 1 = 0 \\ x = 1 \\ or \\ x - 2 = 0 \\ x = 2$

Roots of equation,

roots of the equation are 1 and 2

Verification,

For x=1

in the given equation,

x²-3x+2=0

as x=1

LHS=1²-3+2

=3-3

=0=RHS

hence it is true

For x=2

in the given equation,

x²-3x+2=0

as x=1

LHS=2²-6+2=6-6=0

=RHS

hence it is true

Final answer,

roots of the equation are 1 and 2

hope it helps to you☺️