Question

x^2/4+2x+4 factorise the following​

Answer 1

Step-by-step explanation:

$\frac{ {x}^{2} }{4} + 2x + 4 = 0 \\ {x}^{2} + 8x + 16 = 0 \\ {(x + 4)}^{2} = 0 \\ x + 4 = 0 \\ x = - 4$

Answer 2

Answer:

x^2+8x+16/4=0

x^2+8x+16=0

x^2+(4x+4x)+16=0

x^2+4x+4x+16=0

x(x+4)+4(x+4)=0

(x+4)+(x+4)=0

x=-4,x=-4