x ² - 4√2x + 6 in factorization method
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Solution:-
By Splitting the Middle Term Method!
=) x² - 4√2x + 6
=) x² - ( 3√2 + √2)x + 6
=) x² - 3√2x - √2x + 6
=) x ( x - 3√2) - √2 ( x - 3√2)
=) ( x -3√2) ( x - √2)
=) [ x = 3√2] and [ x = √2 ]
By Completing the Square Method!
=) x² - 4√2x + 6
=) x² - 4√2x = -6
=) x² - 4√2x + ( 2√2)² - ( 2√2)² = - 6
=) x² - 4√2x + ( 2√2)² = ( 2√2)² - 6
=) [ x - 2√2 ]² = 8 - 6
=) x - 2√2 = √2
=) x = 2√2 ± √2
For +√2
=) x = 2√2 + √2 = 3√2
For -√2
=) x = 2√2 - √2 = √2
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