Question

x^2+4√3x-15 findzeroes and in relation between the zeros and coefficients​

Answer 1

=x^2+4√3-15=0

=x^2+5√3-√3x-15=0 ( using splitting method

=x(x+5√3)-√3(x+5√3)

=(x-√3)=0

=x=√3

Andx+5√3=0

x=-5√3=0

√3 and -5√3 is zeroes of given quadratic polynomial.

Hope it helps you...

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Answer 2

Answer:

Step-by-step explanation:

x^2+5sqrt(3)x-sqrt(3)x-15=0

x(x+5sqrt(3))-sqrt(3)(1+5sqrt(3))

=(x-sqrt(3))(x+5sqrt(3))

(x-sqrt(3))(x+5sqrt(3))=0

x-sqrt(3)=0

x+5sqrt(3)=0

x=sqrt(3)

x=-5sqrt(3)

sum of roots=(-b/a)

-5sqrt(3)+sqrt(3)=-(4sqrt(3))

-4sqrt(3)=-4sqrt(3)

so sum of roots is same as the coefficients

product of roots=(-5sqrt(3)(sqrt(3)=-15

-15=-15

product of roots are same as the coefficients