Math, asked by kriya8404, 10 months ago

x^2/4+y^2/9+xy/3 when, x=2,y=3 find the value​

Answers

Answered by Anonymous
1

x^2/4 + y^2/9+xy/3

(x/2 + y/3 )^2

put x = 2 and y=3

(2/2 + 3/3)^2

(1+1)^2

2^2

4

Answered by vikrantTalwar
1

Step-by-step explanation:

x=2

y=3

therefore,

=2^2/4 + 3^2/9 + 2*3/3

=4/4+9/9+6/2

=1+1+2

=4

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