Question

x∆2+4abx-(a∆2-b∆2)2 factorise it

Answer 1

x^2 + 4abx - (a^2 - b^2)^2

= x^2 + 4abx - a^4 - b^4 + 2a^2b^2

= x^2 + 4abx - a^4 - b^4 + 2a^2b^2 + 2a^2b^2 - 2a^2b^2

= (x^2 + 4abx + 4a^2b^2) -(a^4 + b^4 + 2a^2b^2)

= (x + 2ab)^2 - (a^2 + b^2)^2

=(x + 2ab + a^2 + b^2)(x + 2ab - a^2 - b^2)

OR

[x + (a+b)^2]*[x - (a-b)^2]

Answer 2

Answer:

(x-a^2-2ab+b^2)(x-a^2-2ab+b^