Question

x^2-4ax-b+4a^2 solve for x​

Answer 1

Answer:

Solve for x : x  2  −4ax−b  2  +4a  2  =0

Step-by-step explanation:

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Answer 2

Answer: x= 2a+b or 2a-b

Step-by-step explanation:

x^2-4ax+4a^2-b^2=0

x^2-2*2a*x+(2a)^2-(b)^2=0

(x-2a)^2-(b)^2=0

(x-2a-b)(x-2a+b)=0

x-2a-b=0        x-2a+b=0

x=b+2a          x=2a-b

Therefore, x= 2a+b or 2a-b