Question

x^2 +4x+3 find zeroes of quadratic polynomials​

Answer 1

Sol: Given  α and β are zeroes of the polynomial f(x) = x2- 4x + 3 α+ β = 4 αβ = 31) (3α + 3β) = 3x 4 = 12 3α x 3β = 9 x 3  =  27. If 3α, 3β are zeros of the quadratic polynomial then the equation is  x2 -(3α + 3β)x + 9αβ = 0 then x2 - 12x + 27 = 0. 2)(1/2α + 1/2β) = (α + β) / 2αβ  = 4 / 6 = 2 / 3. 1/4αβ  = 1 /12 If 1 / 2α, 1 / 2β are zeros of the quadratic polynomial then the equation is  x2 -(1 / 2α + 1 / 2β)x + 1 / 4αβ = 0 then x2 -(2 / 3)x + 1 / 12 = 0 12x2 - 8x + 1  = 0.

thank you matee

Answer 2

we have

x²+4x+3=0

x²+3x+x+3=0

x(x+3)+1(x+3) =0

( x+1)(x+3) =0

x=-1 or -3

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I hope my answer is clear to you