x^2+4x-320=0 solve using quadratic formula
Answers
Factoring x2-4x-320
The first term is, x2 its coefficient is 1 .
The middle term is, -4x its coefficient is -4 .
The last term, "the constant", is -320
Step-1 : Multiply the coefficient of the first term by the constant 1 • -320 = -320
Step-2 : Find two factors of -320 whose sum equals the coefficient of the middle term, which is -4 .
-320 + 1 = -319
-160 + 2 = -158
-80 + 4 = -76
-64 + 5 = -59
-40 + 8 = -32
-32 + 10 = -22
-20 + 16 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -20 and 16
x2 - 20x + 16x - 320
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-20)
Add up the last 2 terms, pulling out common factors :
16 • (x-20)
Step-5 : Add up the four terms of step 4 :
(x+16) • (x-20)
Which is the desired factorization
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Answer:
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