Question

x^2 -4x + 4 = 0 determine the nature of the root​

Answer 1

For finding nature of roots or quadratic equation we will first find its discriminant which is equal to b^2-4ac

where a,b,c are coffecient of x^2,x and x^0 respectively.

(-2)^2-4*(-4)*1

=20

So we can see that it is positive which implies roots are real and unequal.

Hope it helps

Answer 2

Answer:

x²-4x+4=0

D= b²-4ac

where a=1, b=-4, c=4

(-4)² -4(1×4)

16-4×4

16-16

=0

D=0

so, roots are real and equal