Question

X^2+4x+5=0 find nature of root

Answer 1

Answer:

HERE IS YOUR ANSWER!

=)X²+4x+5

D = b²-4ac

= (4)²-4(5)(1)

16 - 20

=) - 4

D<0

The real root doesn't exist

Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\pink{ {x}^{2} + 4x + 5 = 0} \\ \sf\green{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} } \\ \sf\blue{ = > x = \frac{ - 4± \sqrt{ {4}^{2} - 4 \times 1 \times 5} }{2 \times 1} } \\ \sf\orange{ = > x = \frac{ - 4± \sqrt{16 - 20} }{2} } \\ \sf\red{ = > x = \frac{ - 4± \sqrt{ - 4} }{2} } \\ \sf\pink{ = > x = \frac{ - 4±4i}{2} \: \: \: \: \: \: \: \: ( \sqrt{ - 1} = i) } \\ \sf\blue{ = > x = - 2±2i} \\ \sf\purple{x = - 2 + 2i, - 2 -2i } \\ \large\boxed{ \fcolorbox{red}{blue}{hope \: it \: help \: you}}$