x^2-4x+5 find roots by qudratic formula
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we know that D= b²-4ac
=(-4)²-4(1)(5)
=16-9
=7
x = -b +√D / 2a
x = -(-4)+√7 /2(1)
x = 4+√7 / 2 or x =4 - √7 /2
the roots of equation is 4+√7 / 2 and 4 - √7 / 2
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