Question

x^2+4x-5 find zero of the polynomial​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

${x}^{2} + 4x - 5 = 0 \\ {x}^{2} + (5 - 1)x - 5 = 0 \\ {x}^{2} + 5x - x - 5 = 0 \\ x(x + 5) - 1(x + 5) = 0 \\ (x + 5)(x - 1) = 0 \\ x = - 5 \: or \: 1$

So, the zeros of the polynomial are -5 and 1.