Question

X^2-(5+i)x+(8-i)=0 find square root of above equation

Answer 1

2x² / 5 - x/1 - 3/5 = 0

By Taking LCM ,

2x² - 5x - 3 = 5* 0

2 x² - 5x - 3 = 0

By Prime factorisation { (2x²) * (-3)= -6x² , also -6x ² = - 6x * 1 x , and -6x + 1x = -5x }

2 x² - 6x + 1 x + 3 = 0

2x ( x -3 ) +1 ( x + 3 ) = 0

(2x+1 ) ( x - 3 ) = 0

2x + 1 = 0 or x -3 = 0

x = - 1 / 2 or x = 3

x = - 1 / 2 and 3 are ROOTS of above quadratic equation.