Math, asked by sahukrishna433, 1 year ago

X^2+5x-25=0.find the value of x

Answers

Answered by Raunakc
0

Answer:

x = ( - 5 + 5 \sqrt{5} )  \div 2

x = ( - 5 - 5 \sqrt{5} ) \div 2

Step-by-step explanation:

x² +5x -25=0

D = b²-4ac

=5² -4(-25)

=125

x=(-b±√D)/2a

x=(-5 ± 5√5)/2

x=(-5+5√5)/2

and

x= (-5-5√5)/2

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