Question

x^2-5x-6=0 factor method​

Answer 1

Answer:

factor of $x^{2}-5x-6$ = $(x+1)(x-6)$

Step-by-step explanation:

here, factor of $x^{2}-5x-6=0$

By splitting middle term

⇒ $x^{2}+x-6x-6=0$

⇒ $x(x+1)-6(x+1)=0$

⇒ $(x+1)(x-6)=0$

so, $x+1=0$                     and

$x-6=0$

⇒ $x=-1$

⇒ $x=6$

hope it will help you.